We only need to set the first byte to 0, but gcc likes to zero out the rest of the string with memset() when using this initialization style. Signed-off-by: Mike Frysinger <vapier@gentoo.org> Signed-off-by: Austin Foxley <austinf@cetoncorp.com>
@@ -51,10 +51,12 @@
static const char *
inet_ntop4(const u_char *src, char *dst, size_t size)
{
- char tmp[sizeof ("255.255.255.255") + 1] = "\0";
+ char tmp[sizeof ("255.255.255.255") + 1];
int octet;
int i;
+ tmp[0] = '\0';
+
i = 0;
for (octet = 0; octet <= 3; octet++) {