12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455565758596061 |
- /* Copyright (C) 1993, 1995, 1997, 2003 Free Software Foundation, Inc.
- This file is part of the GNU C Library.
- Contributed by David Mosberger (davidm@azstarnet.com).
- The GNU C Library is free software; you can redistribute it and/or
- modify it under the terms of the GNU Lesser General Public
- License as published by the Free Software Foundation; either
- version 2.1 of the License, or (at your option) any later version.
- The GNU C Library is distributed in the hope that it will be useful,
- but WITHOUT ANY WARRANTY; without even the implied warranty of
- MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
- Lesser General Public License for more details.
- You should have received a copy of the GNU Lesser General Public
- License along with the GNU C Library; if not, write to the Free
- Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
- 02111-1307 USA. */
- #include <features.h>
- #include <errno.h>
- #include <sys/syscall.h>
- #include <signal.h>
- /* When there is kernel support for more than 64 signals, we'll have to
- switch to a new system call convention here. */
- static __inline__ _syscall2(int, osf_sigprocmask, int, how, unsigned long int, setval);
- libc_hidden_proto(sigprocmask)
- int
- sigprocmask (int how, const sigset_t *set, sigset_t *oset)
- {
- unsigned long int setval;
- long result;
- if (set)
- setval = set->__val[0];
- else
- {
- setval = 0;
- how = SIG_BLOCK; /* ensure blocked mask doesn't get changed */
- }
- result = osf_sigprocmask(how, setval);
- if (result == -1)
- /* If there are ever more than 63 signals, we need to recode this
- in assembler since we wouldn't be able to distinguish a mask of
- all 1s from -1, but for now, we're doing just fine... */
- return result;
- if (oset)
- {
- oset->__val[0] = result;
- result = _SIGSET_NWORDS;
- while (--result > 0)
- oset->__val[result] = 0;
- }
- return 0;
- }
- libc_hidden_def(sigprocmask)
|